20=29T-5T^2

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Solution for 20=29T-5T^2 equation:


Simplifying
20 = 29T + -5T2

Solving
20 = 29T + -5T2

Solving for variable 'T'.

Reorder the terms:
20 + -29T + 5T2 = 29T + -29T + -5T2 + 5T2

Combine like terms: 29T + -29T = 0
20 + -29T + 5T2 = 0 + -5T2 + 5T2
20 + -29T + 5T2 = -5T2 + 5T2

Combine like terms: -5T2 + 5T2 = 0
20 + -29T + 5T2 = 0

Factor a trinomial.
(4 + -5T)(5 + -1T) = 0

Subproblem 1

Set the factor '(4 + -5T)' equal to zero and attempt to solve: Simplifying 4 + -5T = 0 Solving 4 + -5T = 0 Move all terms containing T to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -5T = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -5T = 0 + -4 -5T = 0 + -4 Combine like terms: 0 + -4 = -4 -5T = -4 Divide each side by '-5'. T = 0.8 Simplifying T = 0.8

Subproblem 2

Set the factor '(5 + -1T)' equal to zero and attempt to solve: Simplifying 5 + -1T = 0 Solving 5 + -1T = 0 Move all terms containing T to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1T = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1T = 0 + -5 -1T = 0 + -5 Combine like terms: 0 + -5 = -5 -1T = -5 Divide each side by '-1'. T = 5 Simplifying T = 5

Solution

T = {0.8, 5}

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